Question

Triangle abc is a right triangle at b and d is mid point of bc prove ac=4ad-3ab

Answer 1

Answer:

Step-by-step explanation:

In right ABC, using Pythagoras theorem, we have:

AC2 = AB2 + BC2 ...(1)

In right ABD, using Pythagoras theorem, we have:

AD2 = AB2 + BD2

BC2 = 4AD2 - 4AB2 ...(2)

Substituting (2) in (1), we get,

AC2 = 4AD2 - 3AB2

Hence, proved.