Question

triangle ABC is an equilateral triangle. AD bisects angle BAC. show that triangle ABD is congruent to triangle ACD​

Answer 1

In △ ABC,

AB = BC = CA,

AD ⊥ BC, BE ⊥ AC,

Proof: In △ ADC and △ BEC

∠ADC = ∠BEC (each 90°)

∠ACD = ∠BCE (common)

and AC = BC (Sides of an equilateral triangle)

∴ △ ADC ≅ △ BEC (A.A.S. Axiom)

Hence, (i) AD = BE (c.p.c.t)

And (ii) BD = CE (c.p.c.t)

Hence proved.

Answer 2

Answer:

AB=AC

Therefore ,ABC is an isosceles triangle in which AB=AC.

Hence provide