triangle ABC is an equilateral triangle of area 16 root 3 cm square find the area of a square that is formed by the altitude of triangle ABC
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Area of equilateral ∆=16√3
let the sides be a
then
area of equilateral ∆=√3/4a^2
16√3=√3/4a^2
16√3×4÷√3=a^2
64√3/√3=a^2
64=a^2
a=8
area of ∆=1/2×h×b
16√3=1/2×h×8
16√3=4×h
16√3/4=h
4√3=h
area of square formed by altitude=4√3^2
area of sq.=16×3=48
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