Question

Triangle ABC is an equilateral triangle . point P is an base BC such that PC= 1/3 BC,if AB =6cm find AP

Answer 1

Let us draw perpendicular AD on BC, by congruence, BD=1/2 BC=3cm
AP^2=AD^2+PD^2
=AB^2-BD^2+(BP-BD)^2
=6^2-3^2+(4-3)^2
=36-9+1=28
AP=2 Sq root 7 cm