Triangle ABC is an equilateral triangle with each side of length 2p if AD perpendicular to BC then what is the value of AD
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Given, equilateral triangle ABC, AD⊥BC
Since, it is an equilaateral triangle, the perpendicualr also bisects the side.
Hence, BD=DC or BD= 1/2BC= 1/2AB
Now, In △ABD, we have;
AB 2 =AD ²+BD²
⇒AB ² −BD ²=AD ²
⇒BC ²−BD ² =AC²
⇒(2CD) ²−CD ²=AD ²
⇒3CD ²=AD ²
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