Math, asked by deepuwinssp4217, 2 days ago

. Triangle ABC is an equilateral triangle with each side of length 2p. If AD parellaer BC then the value of AD is

Answers

Answered by amitnrw
0

Given :  Triangle ABC is an equilateral triangle with each side of length 2p.  AD ⊥ BC  

( correction in Question AD parallel BC should be AD perpendicular BC)

To Find :  value of AD is

Solution:

ABC is an equilateral triangle hence all side lengths are equal

AB = BC = AC = 2p

AD ⊥ BC  

in ΔADB and ΔADC

AD = AD   common

AB  = AC    ( Equal sides of equilateral triangle)

∠ADB = ∠ADC  = 90°   given

=> ΔADB ≅  ΔADC  ( using RHS Congruency)

RHS - Right angle Hypotenuse congruence

Corresponding parts of congruence triangles are congruent

Hence  BD = CD

BD + CD = 2p

=> BD = CD = p

in Δ ABD  

Using Pythagorean theorem:

square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two perpendicular sides.

=> AB² = AD² + BD²

=> (2p)² = AD² + p²

=>  4p² = AD² + p²

=> AD² = 3p²

=> AD = √3 p

Value of AD is  √3 p

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