Math, asked by visheshaggarwal777, 6 hours ago

Triangle ABC is an isocelese triangle with AB=AC and AD is the altitudeof the triangle. Prove that AD is also the median of the triangle​

Answers

Answered by chsumanth88762
1

Answer:

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Step-by-step explanation:

Hence AD bisects angle A and hence AD is an angle bisector of the triangle ABC. Also, since AD is perpendicular to BC and AD bisects BC, AD is a perpendicular bisector of the triangle ABC. Hence AD is an altitude, a median, an angle bisector as well as a perpendicular bisector of the triangle ABC. Hence proved.

Answered by gokarnpimoli
4

Answer:

Hence AD bisects angle A and hence AD is an angle bisector of the triangle ABC. Also, since AD is perpendicular to BC and AD bisects BC, AD is a perpendicular bisector of the triangle ABC. Hence AD is an altitude, a median, an angle bisector as well as a perpendicular bisector of the triangle ABC. Hence proved.

Step-by-step explanation:

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