Triangle ABC is an isolceles triangle with AB= AC=13cm the length of the altitude from A on BC is 15cm .find BC
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Given: let triangle ABC be an isosceles triangle in which AB=AC = 13cm
Let AD be the altitude on BC where
AD = 15cm
To find: length of BC
Solution: in triangle ABD and triangle ACD.
AB= AC
AD =AD
Angle ADB = angle ADC = 90°
So triangle ABD and triangle ADC are congruent to each other.
So BD = DC
In triangle ADC,
By Pythagoras theorem.
AC² = AD² + DC²
13² = 15² + DC²
DC = 7.4cm
BC = 14.8 cm
I hope my answer will help you
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