Question

triangle ABC is an isosceles right angled triangle in which angle= 90°. find angle B​

Answer 1

ANSWER :-

Given :-

An isosceles ∆ ABC which is right angled at A.

To Find :-

Angle B

Now,

Let angle B = x

It is an isosceles triangle .

so, AB = AC

Also,

Angle B = Angle C ( angle opposite to ㅤequal sides are equal )

$\therefore$ Angle B = Angle C = x .

Angle A + Angle B + Angle C = 180 ( angle sum property)

so,

ㅤ90 + x + x = 180

ㅤ2x = 180 - 90

ㅤ2x = 90

ㅤx = $\dfrac{90}{2}$

ㅤx = $\cancel{\frac{90}{2}}$

ㅤx = 45

$\therefore$ Angle B = 45 degree.

Answer 2

Answer:

ANSWER :-

Given :-

An isosceles ∆ ABC which is right angled at A.

To Find :-

Angle B

Now,

Let angle B = x

It is an isosceles triangle .

so, AB = AC

Also,

Angle B = Angle C ( angle opposite to ㅤequal sides are equal )

Angle B = Angle C = x .

Angle A + Angle B + Angle C = 180 ( angle sum property)

so,

ㅤ90 + x + x = 180

ㅤ2x = 180 - 90

ㅤ2x = 90

ㅤx =  90/2

ㅤx = 45

Angle B = 45 degree.

Step-by-step explanation: