Question

Triangle ABC is an isosceles right triangle in which angle A = 90 degree and BC = 6 CM. Then AB=?(a) 8 cm(b) 18 cm(c) 32 cm(d) 12 cmPlease tell the answer with full explanation....

Answer 1

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Answer 2

Thus, The value of sides $AB$ is $3\sqrt{2} \,cm$

Step-by-step explanation:

Given,

$\triangle ABC$ is an isosceles right triangle in which $\angle A=90$° and $BC=6cm$

∵ $\triangle ABC$ is  isosceles right triangle.

∴ $AC=AB$

From Pythagorean Theorem,

                                              In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

From figure,

$BC^{2}=AC^{2}+AB^{2}$

⇒$2AB^{2} =6^{2}$ (∵$AC=AB$ )

⇒$AB^{2} =\frac{36}{2}$

⇒$AB=\sqrt{18}$

∴$AB=3\sqrt{2}$

So, The value of sides $AB$ is $3\sqrt{2} \,cm$