Question

Triangle ABC is an isosceles triangle and BC is the diameter of the circle. What is the area of the triangle? B C=10 cm

​

Answer 1

Answer:

i think your question is not complete but still tried to help you.

i think this is the answer you are looking for.

please dont mind if my answer is not fully correct because your question is incomplete.

Step-by-step explanation:

Answer 2

Given:

BC=10cm

BC is the diameter of the circle

To find:

Area of the triangle ABC

Solution:

The area of the triangle ABC is 25 $cm^{2}$.

We can find the area by following the given steps-

We know that BC is the diameter of the circle and ABC is an isosceles triangle.

Since BC is the longest line in the circle, AB and AC are the equal sides.

The angle BAC=90° since it is an angle in the semi-circle formed by the diameter of the circle.

Now, ABC is a right-isosceles triangle.

Using the Pythagoras theorem,

$AB^{2} +AC^{2} =BC^{2}$

AB=AC
2$AB^{2}$=$10^{2}$

2$AB^{2}$=100

$AB^{2}$=50

AC=AB=$\sqrt{50}$cm

The area of triangle ABC=1/2×base×height

The base and height of the triangle are AB and AC.

So, the area of triangle ABC=1/2×$\sqrt{50}$×$\sqrt{50}$

=1/2×50

=25 $cm^{2}$

Therefore, the area of the triangle ABC is 25 $cm^{2}$.