Question

triangle ABC is an isosceles triangle in which ab= ac. d ,e and f are the midpoints of sides BC ,AC and AB respectively prove that DE=DF​

Answer 1

Answer:

Triangle ABC is an isosceles triangle in which ab= ac. d ,e and f are the midpoints of sides BC ,AC and AB respectively prove that DE=DF​

Step-by-step explanation:

Given, triangle ABC is an isosceles triangle in which AB = AC

Again, D, E, and F are the mid points of the sides BC, AC, and AB respectively.

Let AD intersect FE at M. Join DE and DF.

Since D and E are the mid points of the sides BC and CA respectively,

So, DE || AB and DE = AB/2   {By mid point theorem}

Similarly,

DF || AC and DF = AC/2   {By mid point theorem}

Since AB = AC

=> AB/2 = AC/2

=> DE = DF

#BAL

Answer 2

Answer:

Given, triangle ABC is an isosceles triangle in which AB = AC

Again, D, E, and F are the mid points of the sides BC, AC, and AB respectively.

Let AD intersect FE at M. Join DE and DF.

Since D and E are the mid points of the sides BC and CA respectively,

So, DE || AB and DE = AB/2   {By mid point theorem}

Similarly,

DF || AC and DF = AC/2   {By mid point theorem}

Since AB = AC

=> AB/2 = AC/2

=> DE = DF

Step-by-step explanation:

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