Question

triangle ABC is an isosceles triangle in which AB=AC. Show that angle B= angle C.
(Hint: Draw AP perpendicula to BC) (Using RHS congruence rule)​

Answer 1

Answer:

In △ABP and △ACP

AB=AC (Given)

∠APB=∠APC (Each equal to 90°)

AP=AP (Common)

Therefore, by RHS congruence rule, △ABP≅△ACP

Hence, ∠B=∠C (Corresponding parts of congruent triangles are equal).

Answer 2

Step-by-step explanation:

bin triangle ABP and triangleCBP

AB=AC ,angle BPC=APB,

BP=BP

By RHS congruence ,triangle BPC con

to triangleAPC

by CPCT ,

Angle B=angle B