Triangle abc is an isosceles triangle in which ab=ac.side ba is produced to d such that ad=ab. Show that angle bcd is a right angle
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Answer:
Given:in triangle abc
ab=ac
ba is produced to d
such that ad=ab
to prove=angle bcd=90°
proof:
in abc
ab=ac (given)
so.angle abc =angle bca
in tri. adc
ad=ac
so.angle acd=angle cda
in tri. bcd
angle abc+angle bcd +angle cda=180
so. angle acb +angle abc +angle acd+angleacd=180
2 (acb+acd)=180
acd+acb=90
so. angle bcd=90
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