Math, asked by pari2837, 1 day ago

triangle ABC is an isosceles triangle in which AB equal to AC side BA produced to be such that AD and BC show that angle BCD is a right angle​

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Answered by Nihira5107
1

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Answered by melbinbiju11
3

Answer:

BCD is a right angle

Step-by-step explanation:

angle ABC =angle ACB(Isosceles property)

angle ADC=angle ACD(Isosceles property)

angle ABC + ADC = angle ACB+ACD      (1)

So,angle ABC+ADC+(ACB+ACD)=180 degree

from equation (1),

(angle ACB+ACD) +(angle ACB+ACD)=180degree

2(angle ACB+ACD)=180degree

(angle ACB+ACD)=180/2=90degree

(angle ACB+ACD)=angle BCD=90 degree

Thus proved :)

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