triangle ABC is an isosceles triangle in which AB equal to AC side BA produced to be such that AD and BC show that angle BCD is a right angle
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Answer:
BCD is a right angle
Step-by-step explanation:
angle ABC =angle ACB(Isosceles property)
angle ADC=angle ACD(Isosceles property)
angle ABC + ADC = angle ACB+ACD (1)
So,angle ABC+ADC+(ACB+ACD)=180 degree
from equation (1),
(angle ACB+ACD) +(angle ACB+ACD)=180degree
2(angle ACB+ACD)=180degree
(angle ACB+ACD)=180/2=90degree
(angle ACB+ACD)=angle BCD=90 degree
Thus proved :)
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