triangle ABC is an isosceles triangle right angled at c .then find AC:AB
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This is "Thals Law" equation, so It's law is important.
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ΔABC
Then AB would be the hypotenuse
Hence this is an isoceles Δ
AC=BC
AB^2= AC^2+BC^2
AB^2=AC^2+AC^2. (AC=BC)
AB^2=2AC^2
:. AB^2/2=AC^2
=> :. AC:AB=1:4
And AC/AB = Sinθ
Hope this will help you:)
Then AB would be the hypotenuse
Hence this is an isoceles Δ
AC=BC
AB^2= AC^2+BC^2
AB^2=AC^2+AC^2. (AC=BC)
AB^2=2AC^2
:. AB^2/2=AC^2
=> :. AC:AB=1:4
And AC/AB = Sinθ
Hope this will help you:)
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