Question

triangle ABC is an isosceles triangle which AB=AC. side Bachchan is produced TO D such that AD=AB show that angle angle B D is a right angle​

Answer 1

Solution :

In ABC

( angle opposite to equal sides are equal )

so

Abc = Abc

In ABC

AD = Ab

/ Acd = / AcD

So now ,

In /\ Abc

/ Cab + / Abc + / Abc = 180 op2

/ Cab + 2 / Abc = 180 o

/ Cab = 180 o - 2 / Acb (i)

In.

/ Cad = 180 - 2 / Acd (ii)

So,

/ Cab + / Cad = 180o

Adding (i) and ( ii)

/ Cab + / Cad = 180 o - 2 / Acb + 180o - 2 / Acd

180o = 36o - 2 / Acb - 2 / Acd

2 / Abc + / Acd = 180o

So ,

180° = 90°

2

So ANSWER is = 90°

Answer 2

Answer:

Step-by-step explanation:

Let the angle ABC be x degree.

Since  AB = AC

angle ACB= angle ABC= x.

Since the sum of internal angles angles of a triangle is 180 degree

angle BAC+angle ACB+ angle ABC= 180 degree

i.e. angle BAC + x+x=180

angle BAC=180-2x

therefore angle DAC=180-angle BAC

angle DAC=2X

Similarly angle DAC+angle ACD+ angle CDA=180 degree

since AD=AC

angle ACD =angle angle CDA

by solving the above equation we get

ACD=90-x

therefore angle BCD=BCA+ACD=x+90-x=90 degree

Hence proved