Math, asked by SahityaTyagi, 6 months ago

TRIANGLE ABC is an isosceles triangle with AB =AC. If angle B =40 degrees, what are the measures of angle A and angle C? please send as fast as possible ​

Answers

Answered by MathExpert123
0

Answer:

As AB=AC so, Ax40=AxC and so A+40+C= 180 and it is isosceles. So,          (180-40)/2

= 140/2

= A=70, B=40 and C= 70

Step-by-step explanation:

As its isosceles, you'll have to half it so both degrees are same

Hope it helps

Answered by farhanhoda2006
1

Answer:

Given

AB=AC

B=40

let the angle a and angle c be x.

A=x

C=x

sum of all angles of an isosceles triangle is is 180°

according to the question

40+x+x=180

2x=180-40

2x=140

x=140/2

x=70

x=70°so,2x=70=70x2=140

Step-by-step explanation:

I I hope this can be helpful

Similar questions