triangle ABC is an isosceles triangle with AB=AC . If angle B =40° , what are the measures of angle A and angle C
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Answered by
161
A=100 and C=40
Ab=Ac so angle B = angle C=40 degree becoz triangle is isoceles so
Sum of all angle of triangle are 180degree
So 40+40-180=100
Angle A=100 degree
...........
Ab=Ac so angle B = angle C=40 degree becoz triangle is isoceles so
Sum of all angle of triangle are 180degree
So 40+40-180=100
Angle A=100 degree
...........
kanu3770:
can you solve it
Answered by
127
Heya!
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↪Refer to the Attachment for the figure ↪
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◾Given that , ∆ABC is an isoceles triangle .
◾ AB = AC .
◾Measure of Angle B = 40°
⭐Now , if Angle B = 40°
Then Angle C = 40° [ Angles opposite to equal sides are equal ]
◾Now we can apply Angle Sum Property to find Angle A => x
x + 40 + 40 = 180
x + 80 = 180
x = 180 - 80
x => 100°
✔Angle C = 40°
✔Angle A = 100°
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---------
-----------------------------------------------------------------------------------------------------
↪Refer to the Attachment for the figure ↪
-----------------------------------------------------------------------------------------------------
◾Given that , ∆ABC is an isoceles triangle .
◾ AB = AC .
◾Measure of Angle B = 40°
⭐Now , if Angle B = 40°
Then Angle C = 40° [ Angles opposite to equal sides are equal ]
◾Now we can apply Angle Sum Property to find Angle A => x
x + 40 + 40 = 180
x + 80 = 180
x = 180 - 80
x => 100°
✔Angle C = 40°
✔Angle A = 100°
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