Question

triangle ABC is an isosceles triangle with ab is equal to AC is equal to 7.5 cm and BC is equal to 9 cm what will be the height of height from sea to a bid that is CET question mark if the height from a to b c is 4.5 cm find the area of triangle ABC.
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Answer 1

Answer:

1.

In ΔABC, AD=6cm and BC=9cm

Area of triangle= 1/2×base×height

= 1/2×BC×AD

= 1/2×9×6=27 cm²

Again, Area of triangle= 1/2×base×height

⇒27 = 1/2 ×AB×CE

⇒ CE = 27×2/7.5

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm

2.

Area of ∆ =

$\frac{1}{2} \times b \times h$

$= \frac{1}{2} \times 9 \times 4.5$

$= \frac{40.5}{2}$

$= 20.25 \: {cm}^{2}$

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Answer 2

Answer:

In ΔABC, AD=6cm and BC=9cm

Area of triangle= 1/2×base×height

= 1/2×BC×AD

= 1/2×9×6=27 cm²

Again, Area of triangle= 1/2×base×height

⇒27 = 1/2 ×AB×CE

⇒ CE = 27×2/7.5

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm

2.

Area of ∆ =

\frac{1}{2} \times b \times h

2

1

×b×h

= \frac{1}{2} \times 9 \times 4.5=

2

1

×9×4.5