Triangle ABC is congruent to triangle DEF and a B is equal to 12 cm BC is equal to 8 cm AC is equal to 15 cm and D is equal to 18 cm find EF and DF
Answers
Answer:
Answer:-
BC = \frac{28}{5}
5
28
DE = \frac{75}{7}
7
75
Step-by-step explanation:
In this question
We have been given that
ΔABC similar to ΔDEF and sides of triangle is AB = 5cm, AC = 7cm, DF = 15cm and EF = 12cm
We need to find other side of triangle,
so, ΔABC and ΔDEF are similar triangle
similar triangle formula is \frac{AB}{DE}
DE
AB
= \frac{BC}{EF}
EF
BC
=\frac{AC}{DF}
DF
AC
\frac{5}{DE}
DE
5
=\frac{BC}{12}
12
BC
= \frac{7}{15}
15
7
\frac{5}{DE}
DE
5
= \frac{7}{15}
15
7
DE = \frac{75}{7}
7
75
similarly, \frac{BC}{EF}
EF
BC
= \frac{AC}{DE}
DE
AC
\frac{BC}{12}
12
BC
= \frac{7}{15}
15
7
BC = \frac{28}{5}
5
28
Hence, value of other side of triangle BC = \frac{28}{5}
5
28
and DE = \frac{75}{7}
7
75
.....hope it helps
Answer:
this is my answer not sure
