Triangle ABC is congruent to Triangle PQR state which ratio of sides are equal to AB upon PQ
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We have, ( ≈ CONGRUENT)
ΔABC ≈ ΔPQR
So,
ΔABC ~ ΔPQR
By similarity,
AB / PQ = BC / QR = AC / PR
ΔABC ≈ ΔPQR
So,
ΔABC ~ ΔPQR
By similarity,
AB / PQ = BC / QR = AC / PR
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