Triangle ABC is equal to 90 degree BC equal to 10 cm angle c equal to 45 degree find ab and ac
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in ∆ABC
Angle c is 45', angle b is 90'
now we have to find the first angle
90+45+a=180( angle sum property of∆)
135+a=180
a=180-135
a=45
angle a=45'
now tow angle of this triangle are equal means it is an isosceles triangle so it's two sides are also equal
therefore bc=ab=10 CM
now by Pythagoras theorem
ac= 10√2 cm
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