triangle ABC is equal to triangle d e f the area of triangle ABC is 45 CM square and the area of triangle d e f is equal to 20 CM square one side of the triangle ABC is 3.6 CM then the length of the corresponding side of triangle d e f is
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Given △ABC∼△DEF
Hence the ratio of their areas is the ratio of squares of their sides
∴
ar(△DEF)
ar(△ABC)
=
DE
2
AB
2
⇒
45
20
=
DE
2
25
∴DE=7.5 cm
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