Question

Triangle ABC is equilateral find area of the shaded part

Answer 1

I THINK THE ANSWER WILL BE 30.

HOPE IT HELPED

Answer 2

Answer:

The Area of the Shaded Part = 19.3 cm²

Step-by-step explanation:

Provided that, ∆ABC is an equilateral triangle.

Area of an equilateral triangle = √3a²/4. [ a is given as 10cm]

= 100√3 / 4 = 25√3 cm²

Let the central point be O.

Then, the Area of the shaded part =

Area of ∆ABC - Area of ∆BOC

∆BOC is a right triangle ( provided in the image )

BO = 6 cm

BC = 10 cm.

Then OC = √(BC² - BO²). [ Using Pythagoras theorem]

=> OC = √(10² - 6²)

= √(100 - 36)

= √64 = 8cm

Since ∆BAC is a right triangle, altitude of the triangle = height of the triangle ( 6cm ) and base of the triangle is 8cm

Area of ∆BAC = 1/2 bh

= 1/2 × 8 × 6 = 24cm²

The Area of the shaded part =

Area (∆ABC) - Area (∆BOC) = 25√3cm² - 2cm²

Lets assume the value of √3 = 1.732

Then, 25√3 cm² = 25 × 1.732 = 43.3 cm²

Then the shaded area = 43.3 cm² - 24 cm²

= 19.3 cm²