Triangle ABC is equilateral in the diagram at left below, and ABDE, BCFG, and CAHI are squares Prove that triangle DFH is equilateral.
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Answer:
Given: △ABC and △BDE are equilateral triangles.
D is midpoint of BC.
Since, △ABC and △BDE are equilateral triangles.
All the angles are 60
∘
and hence they are similar triangles.
Ratio of areas of similar triangles is equal to ratio of squares of their sides:
Now,
A(△ABC)
A(△BDE)
=
BD
2
BC
2
A(△BDE)
A(△ABC)
=
BD
2
(2BD)
2
....Since BC=2BD
A(△BDE)
A(△ABC)
=4:1
Step-by-step explanation:
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