Question

triangle ABC is equilateral triangle

Answer 1

Let the side of the ∆ be a unit .

Now ,

$\sqrt{3} a \div 2 = 4$

→a = 8/root 3

Now area of ∆ ABC =

$\sqrt{3} \times 8 \times 8 \div 3$

64 / root 3×4 = 16 / root 3