Triangle ABC is inscribed in a circle with center X, where ∠ABC = 90 , BC = 18, and AB = 80. The altitude from point B intersects AC at point D. What is the distance between point X and point D?
Answers
Answered by
0
From the figure, X is the centre.
And AC is the diameter.
Since perpendicular drawn from a point on a circle to the diameter passes through the centre,X and D must coincide.
Hence, distance between X and D is 0.
And AC is the diameter.
Since perpendicular drawn from a point on a circle to the diameter passes through the centre,X and D must coincide.
Hence, distance between X and D is 0.
ivanzhengib:
sorry but it is wrong
Similar questions