Question

Triangle ABC is inscribed in a circle with Centre O , AB = AC , OP perpendicular AB and OQ perpendicular AC. Prove that PB = QC

Answer 1

Answer:

Given

AB=AC. EQU (1)

OP and OQ are drawn perpendicularly to AB and AC

AB=AP+PB

AB=2PB. ( The line drawn perpendicularly to the chord of a circle, divides into 2 equal parts)

similarly,

AC=AQ+CQ

AC=2QC

From equ(1)

AB=AC

2PB=2QC

PB=PC

Hence proved