Question

triangle ABC is isosceles and BD = CD. Prove that angle ABD = angle ACD​

Answer 1

Answer:

so basically there is a median that is of the mid-point of the triangle ABC on line BC

so we join A to D(mid-point of the line BC)

and we know that ABC is a isosceles Δ

so AD. is a perpendicular bisector

so, in ΔABD and ΔACD

AD=AD

angle D=90°

BD=CD

so, ΔABD ≈ΔACD

therefore, angleABD=angleACD( C.P.C.T.)

Hence proved

Answer 2

Answer:

done !! see it in #caption