Question

Triangle ABC is isosceles and right angled at B.If AB = 4 units, find the value of sinA​

Answer 1

SinA = Perpendicular/ hypotenuse
SinA= AB/AC
SinA= 4/4 ( ABC is isosceles triangle)
SinA = 1

Answer 2

Step-by-step explanation:

AB=BC=4 units

AB^2 + BC^2=AC^2

(4)(4) + (4)(4) =AC^2

16+16==>32=AC^2

AC=√32

AC=4√2

sinA=opp

hyp

SinA=BC/AC

SinA=4/4√2

SinA=1/√2