Question

Triangle ABC is isosceles with AB = AC = 7.5 cm & BC = 9 cm.THe height AD from A to BC, is 6 cm.Find the area of triangle ABC.What wil be the height from C to AB i.e., CE?

Answer 1

are of triangle will be 54/2=27
and the height of altitude qill be
7.2cm

Answer 2

Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM

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