Question

Triangle ABC is isosceles with AB = AC=7.5 cm and BC =9 cm (Fig 11.26). The height
AD from A to BC, is 6 cm. Find the area of AABC. What will be the height from C
to AB i.e., CE?​

Answer 1

Step-by-step explanation:

In ΔABC, AD=6cm and BC=9cm

Area of triangle=21×base×height=21×BC×AD

=21×9×6=27 cm2

Again, Area of triangle=21×base×height=21×AB×CE

⇒27=21×7.5×CE

⇒ CE=7.527×2

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm.

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM