Question

triangle ABC is isosceles with AB equals to AC equal to 7.5 cm and BC equal to 9 CM the height from a to BC is 6 cm . what will be the height from c to ab ​

Answer 1

In Δ ABC, AD = 6 cm and BC = 9 cm, AB = AC = 7.5 cm.

=> Area of triangle = 1/2 x base x height  

=> 1/2 x BC x AD  

=> 1/2  x 9 x 6 = 27 cm^2.

Again,

Area of triangle = 1/2 x base x height

=> 27 = 1/2 x AB x CE  

⇒ 27 = 1/2 x 7.5 x CE  

⇒ CE = (27 x 2) / 7.5  

⇒ CE = 7.2 cm  

Thus, height from C to AB i.e., CE is 7.2 cm.

#BeBrainly

Answer 2

Answer:

• area of triangle ABC =1/2 * base * height
• area of triangle =1/2 *9*6=27cm
• Now AB is base and EC is height
• Again Area of triangle = 1/2 * base * height
• 27cm = 1/2 * 7.5 * EC
• EC = 27 *2 /7.5 = 7.2 cm