Triangle ABC is isosceles with
AC=BC and
Points D and E are chosen on segment AB so that
AD=DE=EB
find angle CDE in degrees
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Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD
Given AB=AC
∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)
Given BE=CD
Then BE−DE=CD−DE
ORBC=CE......................................(2)
In ΔABD and ΔACE
∠ABD=∠ACE ( From 1)
BC=CE (from 2)
AB=AC ( GIven)
∴ΔABD≅ΔACE
So AD=AE [henceproved]
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