triangle abc is rectangled at a. Ad is parallel to bc if Ab = 5cm BC = 13cm
Ac = 12 find the area of triangle ABC also find the length of AD
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Answer:
In right angles triangle BAC, AB=5cm and AC=12cm
Area of triangle=
2
1
×base×height=
2
1
×AB×AC
=
2
1
×5×12=30cm
2
Now, in ΔABC,
Area of triangle ABC=
2
1
×BC×AD
⇒30=
2
1
×13×AD
⇒ AD=
13
30×2
=
13
60
cm.
Step-by-step explanation:
hope it's help you
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