triangle ABC is right angle at A. ADis perpendicular to BC If AB=8cm,BC=10cm,AC=6.find the area of triangleABC and the length of AD
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please, give me a figure of this question. Then I try to solve this question.
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Area of ∆ = 24 cm^2 , Length of AD= 5cm.
Step-by-step explanation:
Area of ∆= 1/2*b*h
= 1/2*8*6
= 1/2*48
= 24cm^2
Length of AD= 10/2 ( because AD is perpendicular )
= 5 cm
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