Question

triangle ABC is right angle at c and CD | AB . if angle A = 55 *, find (1) angle ACD (2) angle BCD (3) angle CBD​

( Full explanation ). fast

Answer 1

Answer:

In the triangle ABC , 3. Angle BDC = 90� .given

Therefore Angle CBD +BDC +BCD= 180.Sum of angles of triangle

40�+90�+BCD=180�

130�+BCD=180�

BCD=50�

Angle ACB=90 .given

Angle ACB=Angle ACD+BCD

90�=ACD+50�

Angle ACD=40�

Angle ABC=40� .(A-D-B)

ACB+ABC+BAC=180� .Sum of angles of triangle

Therefore 90�+40�+BAC=180�

130�+BAC=180�

BAC=50�

Answer 2

Answer:

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