triangle ABC is right angled and right angled at a.a circle is inscribed in it the length of the two sides containing the right angle are 6 cm and 8 cm find the radius of the circle
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here's your answer dude.
first const the sides
by phytagores theorem let O be the centre and F is pt touching AC
AC^2 = BC^2 + AB^2
AC^2 = 6^2 + 8^2
AC^2 = 36 + 64
AC^2 = 100
AC = 10
Radius = AF+FC
10=(8-x) + (6-x)
10 = 14 - 2x
x = 2cm
therefore the radius will be 2cm
hope it helpz plz mark as brainliest
first const the sides
by phytagores theorem let O be the centre and F is pt touching AC
AC^2 = BC^2 + AB^2
AC^2 = 6^2 + 8^2
AC^2 = 36 + 64
AC^2 = 100
AC = 10
Radius = AF+FC
10=(8-x) + (6-x)
10 = 14 - 2x
x = 2cm
therefore the radius will be 2cm
hope it helpz plz mark as brainliest
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