Question

Triangle ABC is right angled at A. AD is drawn perpendicular to BC. If AB = 5 cm and
AC 12 cm, find the area of AABC. Also find the length of AD.​

Answer 1

Step-by-step explanation:

Area of right triangle ABC

$=\frac{1}{2}\times AB\times AC=\frac{1}{2}\times5\times12=30cm^2$

Area of \triangle ABC=$\frac{1}{2}\times BC\times$

30cm^2=$\frac{1}{2}\times13cm\times$

$AD=\frac{30\times2}{13}$

$=\frac{60}{13}$

4.62