Question

Triangle abc is right angled at a. ad is drawn perpendicular to bc . If ab= 5 cm and ac =12 cm, find the area of triangle abc .also find the length of AD

Answer 1

Answer:

AREA = 30cm^2

AD=4.615cm

Step-by-step explanation:

2According to Pythagoras theorem,

(AB)^2 +(AC)^2 =(BC)^2

(12)^2 +(5)^2= (BC)^2

144+25=(BC)^2

169=(BC)^2

BC=13 cm

As it is a right angled triangle,

1/2*AB*AC=area

1/2*5*12=5*6=30

When we take BC as base,

1/2*13*AD=30

13/2*AD=30

AD=30*2/13

AD=4.615cm

Answer 2

Answer:

Step-by-step explanation:

Area of Traingle = 1/2 * Base * Height,

We have two heights and two bases, You need to take either of those which are perpendicular to each other,

Those two sets are (AC, AB) and (AD, BC),

Now area of traingle = 1/2 * 5 * 12 = 30 cm²,

Which is also equal to 1/2 * 13 * AD,

=> 1/2 * 13 * AD = 30 cm²,

=> AD = 60/13 cm,

So therefore Area = 30cm² And AD = 60/13 cm,

Hope you understand, Have a great day !!