Triangle abc is right angled at a. ad is drawn perpendicular to bc . If ab= 5 cm and ac =12 cm, find the area of triangle abc .also find the length of AD
Answers
Answered by
8
Answer:
AREA = 30cm^2
AD=4.615cm
Step-by-step explanation:
2According to Pythagoras theorem,
(AB)^2 +(AC)^2 =(BC)^2
(12)^2 +(5)^2= (BC)^2
144+25=(BC)^2
169=(BC)^2
BC=13 cm
As it is a right angled triangle,
1/2*AB*AC=area
1/2*5*12=5*6=30
When we take BC as base,
1/2*13*AD=30
13/2*AD=30
AD=30*2/13
AD=4.615cm
Answered by
0
Answer:
Step-by-step explanation:
Area of Traingle = 1/2 * Base * Height,
We have two heights and two bases, You need to take either of those which are perpendicular to each other,
Those two sets are (AC, AB) and (AD, BC),
Now area of traingle = 1/2 * 5 * 12 = 30 cm²,
Which is also equal to 1/2 * 13 * AD,
=> 1/2 * 13 * AD = 30 cm²,
=> AD = 60/13 cm,
So therefore Area = 30cm² And AD = 60/13 cm,
Hope you understand, Have a great day !!
Similar questions
English,
7 months ago
Hindi,
7 months ago
English,
1 year ago
Biology,
1 year ago
Environmental Sciences,
1 year ago