triangle ABC is right angled at A. AD is drawn perpendicular to BC if AB = 5 cm and AC = 1 cm find the area of triangle ABC also find the length of AD
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Area of triangle = ½ × base AB × h
area = 2.5 cm²
by Pythagoras theorem,
BC = √26
area of triangle = ½ x base BC x height
2.5 = ½ × √26 x height AD
AD = 5/√26
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