triangle ABC is right angled at A, AD is
perpendicular to BC. If
AB = 5 cm, BC = 13 cm and AC = 12 cm.
Find the area of. Also fond the
length of AD
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Answer:
AB = 5cm, AC = 12 cm, BC = 13 cm.
so, Area = 1/2 × base × height
= 1/2 × 12 × 5 cm²
= 30 cm²
ATQ, in triangle ADC, is right angled at D,
AC = 12 cm, DC = 13/2 = 6.5.
SO, AD² = 12² - 6.5²
AD² = 144 - 42.25
AD² = 101.75
AD × AD = 10.0871205× 10.0871205
AD = 10.0871205
Step-by-step explanation:
hope it helps u
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