triangle ABC is right angled at a. AD is perpendicular to BC. If AB=5 BC=13 AC=12.Find area of triangle ABC. find the length of AD
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In Triangle ABC
AC is the base of 12cm
and AB is the height of 5cm
Now, ar. of triangle=1/2×base(AC)×height(AB)
=1/2×12×5
=30
Now,let AD be the height
Therefore,ar. of triangle=1/2×12×AD
30=6×AD
AB=30/6
AD=5cm
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therefore the length of AD is 5
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