Question

triangle ABC is right angled at A and triangle PQR is right angled at P . if cos B = cos Q , show angle B = angle Q

Answer 1

$here \: is \: your \: answer \: mate$

$in \: triangle \: abc \: and \: pqr$

$\cos(b) = \cos(q) \\ then \\ \frac{cb}{ab} = \frac{rq}{pq} \\ so \: angle \: b = angle \: q \\ angle \: a \: = angle \: p \: \: \: (90 \: degree) \\ so \: triangle \: abc \: is \: similar \: to \: pqr$

$so \: by \: cpct \: angle \: b \: = \: angle \: q$

$mark \: as \: brainlist$