Question

Triangle ABC is right angled at A. M is a point such that AM is perpendicular to BC. Prove that angle BAM = angle ACB

Answer 1

It will be congruent by SAS rule
First
AM common side

Second
If AM is perpendicular means it makes angle of 90 degree so an angle is equal so
Angle AMB=AMC

Third
If it is perpendicular means M is the mid point so
BM=MC

So by SAS it is congruent
And by c.p.c.t we can
Angle BAM = Angle MAC


Hope it helps