Question

Triangle ABC is right angled at B . BD is perpendicular to AC . If AB = 8 cm , BC = 6 cm and AC = 10 cm, find the area triangle ABC . Also find the length of BD​

Answer 1

Answer:

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Answer 2

Area of triangle ABC=24 square cm

BD=4.8 cm

Step-by-step explanation:

AB=8 cm

BC=6 cm

AC=10 cm

Area of triangle=$\frac{1}{2}\times base\times height$

Using the formula

Area of triangle ABC=$\frac{1}{2}\times BC\times AB=\frac{1}{2}\times 6 cm\times 8 cm=24 cm^2$

Area of triangle ABC=24 square cm

Again , using the formula

Area of triangle ABC=$\frac{1}{2}\times AC\times BD$

$24=\frac{1}{2}\times 10\times BD$

$BD=\frac{24\times 2}{10}=4.8 cm$

BD=4.8 cm

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