Question

triangle ABC is right angled at B. BD is perpendicular to AC. Prove that AB^2/BC^2 =AD/CD

Answer 1

Answer:

Triangle ABC is right angled at BD perpendicular to AC then triangle ABD and triangle BCD then angle D is 90 are Common of two triangle BD are common side then two triangle are same S-A-S test AB/BC=BD/CD=AD/BD are congruent side AB/BC= BD+AD/CD+BD AB/BC = AB/BC AB^2/BC^2=AD/CD