Triangle ABC is right angled at 'B'.
'D' and 'E' are the mid-points of AB
and BC respectively. Show that AC2 = 4DE2
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Answer:
Questions is wrong....
correct question is must be ...show that DE2=4AC2
Step-by-step explanation:
IN Triangle ABC,
pytha.the
AC2=AB2+BC2
IN Triangle DBE,
Pythagoras's
DE2=DB2+BE2
=(2AB)2+(2BC)2
=4AB2 + 4BC2
=4(AB2+BC2)
DE2=4AC2
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