Question

Triangle ABC is right angled at B. If AC=26m,BC=10m,find AB​

Answer 1

Answer:

ang. B = 90°

According to Pythagoras theorem

AC ² = AB² + BC²

26² = AB² + 10 ²

676 = AB² + 100

676 - 100 = AB²

AB² = 576

AB = √ 576

AB = 24 m

Answer 2

Answer:

The length of side AB is $24$ m.    

Step-by-step explanation:

Given : ΔABC is right angled at B.

           AC = $26$ m

           BC = $10$ m

To find : AB =?

Solution :

• It is given that ΔABC is right angled at B.

           AC = $26$ m

           BC = $10$ m

• We have to find the length of side AB.
• As the given triangle is right angled triangle, use the Pythagoras theorem.
• Pythagoras theorem states that " In a right angled triangle, the square of hypotenuse side is the addition of squares of other two sides."
• ∴ In a ΔABC, By Pythagoras theorem,

       $AC^{2} =AB^{2} +BC^{2}$

      ∴ $26^{2} =AB^{2} +10^{2}$

       ∴ $676 = AB^{2} +100$

       ∴ $AB^{2} =676-100$

                 $=576$

• Now, taking square roots of both the sides, we get

          ∴  $AB=\sqrt{576}$

                  $=24$ m

• ∴ The length of side AB is $24$ m.